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写一个函数获取一个无符号整型数,并且返回它的“1”比特的数目(也被叫做Hamming weight)。例如,一个32位整型数“11”,转换成二进制是00000000000000000000000000001011,所以这个函数应该返回3。
Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight).For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should return 3.
这道题我之前遇到过,这里就直接贴结果了,稍候我整理一篇关于位运算的博客出来。欢迎大家再来……
class Solution { public: int hammingWeight(uint32_t n) { int count = 0; while (n) { ++count; n = (n - 1) & n; } return count; }};